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Jun 01, · Then by the Fundamental Theorem of Calculus F ′ (x) = f(x) Changing variables u = x t we get g(x) = ∫b af(x t)dt = ∫b x a xf(u)du = F(b x) − F(x a) Differentiating the above we finally have g ′ (x) = F ′ (b x) − F ′ (x a) = f(b x) − f(x a) Share answered Jun 1 ' at 2225 Tony419{ V X e ̃v g ́i s N Z / C ` j o o h Ɋ Â Ă ܂ B s b ` 024 / 04= _ g _ j Z e v g u c ^ b j _ d l h j I G G h \ h k _ e v q _ g d h = e Z \ g u c b g ` _ g _ j i j h _ d l Z I < ;
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X C V B 28,415 likes · 15 talking about this UK Streewear brandExperts are waiting 24/7 to provide stepJan 18, 18 · 3 ObsessiveMathsFreak said This appears to be the definition of the sum of two functions It is valid as long as f and g have the same domains and ranges They don't need the same range Try sin (x) x Share Share
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